Review of background

Within the local density approximation to density functional theory, the total energy of an electronic system is

\begin{displaymath}
E_{tot} = T + E_{el-nuc}+E_{Hartree}+E_{xc},
\end{displaymath}

with

\begin{eqnarray*}
T & \equiv & \sum_i f_i \int \psi_i^*(\vec x) \left( -\frac{1}...
... \, \, dV \\
E_{xc} & \equiv & \int f_{xc}(n(\vec x)) \, \, dV,
\end{eqnarray*}


where

\begin{displaymath}
n(\vec x) \equiv \sum_i f_i \vert\psi_i(\vec x)\vert^2
\end{displaymath}

and

\begin{displaymath}
\nabla^2 \phi(\vec x) = - 4 \pi n(\vec x).
\end{displaymath}

Minimizing the above total energy is equivalent to solving the Schrödinger equation

\begin{displaymath}
-\frac{1}{2} \nabla^2 \psi_i(\vec x) + V(\vec x) \psi_i(\vec x) = E_i
\psi_i(\vec x),
\end{displaymath}

with

\begin{displaymath}
V(\vec x) \equiv V_{nuc}(\vec x) + \phi(\vec x) + V_{xc}(\vec x),
\end{displaymath}

where

\begin{displaymath}
V_{xc}(\vec x) \equiv f'_{xc}(n(\vec x)).
\end{displaymath}

In terms of the electron energies $E_i$ above, an alternative form for the total energy is

\begin{displaymath}
E_{tot} = \sum_i f_i E_i - E_{Hatree} + \int \left[ f_{xc}(n(\vec
x))-f'_{xc}(n(\vec x)) n(\vec x) \right] \, dV.
\end{displaymath}

This first problem of this homework develops the software to compute the exchange-correlation terms in the above equations. The literature always gives $f_{xc}(n)$ in the form $f_{xc}(n) = \epsilon_{xc}(n) n$. In terms of $\epsilon_{xc}$, the quantities we shall need are

$\displaystyle V_{xc}(\vec x)$ $\textstyle \equiv$ $\displaystyle f'_{xc}(n(\vec x))$  
  $\textstyle =$ $\displaystyle \epsilon_{xc}'(n(\vec x)) n(\vec x) + \epsilon_{xc}(n(\vec x))$ (1)

and the exchange-correlation correction energy,

\begin{eqnarray*}
\Delta E_{xc} & \equiv & \int \left[ f_{xc}(n(\vec x))-f'_{xc}...
...\equiv & \int \Delta\epsilon_{xc}(n(\vec x)) n(\vec x) \, \, dV,
\end{eqnarray*}


where
$\displaystyle \Delta\epsilon_{xc}(n(\vec x))$ $\textstyle \equiv$ $\displaystyle \frac{1}{n(\vec x)} \left[ f_{xc}(n(\vec x))-f'_{xc}(n(\vec
x)) n(\vec x) \right]$  
  $\textstyle =$ $\displaystyle \epsilon_{xc}(n(\vec x))-f'_{xc}(n(\vec x))$  
  $\textstyle =$ $\displaystyle \epsilon_{xc}(n(\vec x))-(\epsilon_{xc}'(n(\vec x)) n(\vec x) +
\epsilon_{xc}(n(\vec x)))$  
  $\textstyle =$ $\displaystyle -\epsilon_{xc}'(n(\vec x)) n(\vec x)$ (2)

Tomas Arias 2004-03-12